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Se consideră funcția f:ℝ→ℝ, f(x) = x↑2-4x+2
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admin
Thu Jul 23 2020, 02:53PM

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Se consideră funcția f:ℝ→ℝ, f(x) = x↑2-4x+2. Determinați numerele reale a pentru care f(a) = 2 .

f(a)=a↑2-4×a+2 =>

a↑2-4×a+2=2
a↑2-4×a+2-2=0
a↑2-4×a=0

---------
Δ=b↑2-4ac
---------

a=1
b=-4
c=0




sau varianta doi de rezolvare:

a↑2-4a=a(a-4)
a(a-4)=0 ⇔ a=0






[ Edited Thu Jul 23 2020, 04:03PM ]
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